{"id":16844,"date":"2024-05-11T00:58:11","date_gmt":"2024-05-11T00:58:11","guid":{"rendered":"http:\/\/dudoansongthulo.com\/?p=16844"},"modified":"2024-05-11T00:58:11","modified_gmt":"2024-05-11T00:58:11","slug":"du-doan-xo-mien-bac-lo-xien-2","status":"publish","type":"post","link":"https:\/\/soicau18h.org\/du-doan-xo-mien-bac-lo-xien-2\/","title":{"rendered":"T\u00ecm hi\u1ec3u b\u00ed quy\u1ebft c\u1ee7a chuy\u00ean gia d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean"},"content":{"rendered":"
L\u00e0m sao \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean<\/strong> ng\u00e0y h\u00f4m nay ch\u00ednh x\u00e1c? \u0110\u00f3 l\u00e0 b\u0103n kho\u0103n c\u1ee7a nh\u1eefng ng\u01b0\u1eddi \u0111am m\u00ea v\u1edbi nh\u1eefng con s\u1ed1. Sau \u0111\u00e2y, c\u00e1c b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c c\u00e1ch d\u1ef1 \u0111o\u00e1n l\u00f4 \u0111\u1ec1 s\u00e1t nh\u1ea5t hi\u1ec7n nay. Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng.<\/p>\n B\u00f3ng s\u1ed1 trong soi c\u1ea7u l\u00f4 \u0111\u1ec1<\/strong> c\u1ea7n bi\u1ebft:<\/p>\n C\u1ea7u s\u1ed1 6 l\u00e0 b\u00f3ng c\u1ee7a 1<\/p>\n C\u1ea7u s\u1ed1 7 l\u00e0 b\u00f3ng c\u1ee7a 2<\/p>\n C\u1ea7u s\u1ed1 8 l\u00e0 b\u00f3ng c\u1ee7a 3<\/p>\n C\u1ea7u s\u1ed1 9 l\u00e0 b\u00f3ng c\u1ee7a 4<\/p>\n C\u1ea7u s\u1ed1 0 l\u00e0 b\u00f3ng c\u1ee7a 5<\/p>\n D\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean<\/strong> theo phong th\u1ee7y<\/p>\n Kim = 2. M\u1ed9c = 5. H\u1ecfa = 3. Th\u1ee7y =1. Th\u1ed5 = 4.<\/p>\n Chi\u1ebfu theo b\u00f3ng c\u1ee7a s\u1ed1 nh\u01b0 \u1edf tr\u00ean, ta c\u00f3 : Kim = 7. M\u1ed9c = 0. H\u1ecfa = 8. Th\u1ee7y = 6. Th\u1ed5 = 9.<\/p>\n Trong phong th\u1ee7y c\u00f3 d\u00e3y: Kim -> M\u1ed9c -> H\u1ecfa -> Th\u1ee7y -> Th\u1ed5 -> Kim.<\/p>\n T\u1eeb \u0111\u00f3 quy \u0111\u1ed5i \u0111\u01b0\u1ee3c : 2->5->3->1->4->2 v\u00e0 7->0->6->9->7<\/p>\n T\u1ed5ng s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t:<\/p>\n VD: Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 15326 -> t\u1ed5ng = 1+5+3+2+6 = 17<\/p>\n D\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean hi\u1ec7u qu\u1ea3 c\u1ea7n bi\u1ebft<\/p><\/div>\n L\u00f4 xi\u00ean \u0111\u1ed1i v\u1edbi mi\u1ec1n B\u1eafc v\u00e0 mi\u1ec1n Nam c\u00f3 nh\u1eefng \u0111i\u1ec3m kh\u00e1c nhau. Tuy nhi\u00ean v\u1edbi c\u00e1ch d\u1ef1 \u0111o\u00e1n d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec1u c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng trong nh\u1eefng b\u01b0\u1edbc \u0111\u1ea7u. C\u00f4ng vi\u1ec7c n\u00e0y \u0111\u00f4i khi ti\u1ec1m \u1ea9n nhi\u1ec1u r\u1ee7i ro b\u1edfi nh\u1eefng y\u1ebfu t\u1ed1 kh\u00e1ch quan. B\u1edfi v\u1eady m\u1ed7i l\u1ea7n d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> v\u00e0 \u0111\u1ea7u t\u01b0 v\u1ed1n, b\u1ea1n n\u00ean c\u00e2n nh\u1eafc k\u0129.<\/p>\n \u1ede c\u00f9ng 1 v\u1ecb tr\u00ed c\u1ee7a gi\u1ea3i, c\u0103n c\u1ee9 v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u1ee7a nh\u1eefng ng\u00e0y tr\u01b0\u1edbc, ta c\u1ea7n ch\u1ecdn ra 1 c\u1eb7p s\u1ed1 \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n cho h\u00f4m sau. C\u1ea7u \u1ed5n \u0111\u1ecbnh khi ch\u1ea1y kh\u1ea3 n\u0103ng \u0111\u00fang s\u1ebd t\u1eeb 4 ng\u00e0y tr\u1edf l\u00ean.<\/p>\n L\u00e0m v\u00ed d\u1ee5 \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean<\/strong> d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n C\u0103n c\u1ee9 v\u00e0o k\u1ebft qu\u1ea3 XSMB c\u1ee7a ng\u00e0y 01\/01<\/p>\n 46316<\/p>\n 21028<\/p>\n D\u1ef1 \u0111o\u00e1n c\u1eb7p 68-86, k\u1ebft qu\u1ea3 c\u1ee7a ng\u00e0y 02\/01 c\u00f3 con 68.<\/p>\n Do \u0111\u00f3, theo c\u1ea7u n\u00e0y, ta ti\u1ebfp t\u1ee5c ch\u1ecdn \u1edf c\u00f9ng v\u1ecb tr\u00ed c\u1ee7a k\u1ebft qu\u1ea3 c\u1ee7a ng\u00e0y 02\/01 \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong><\/a> cho ng\u00e0y 03\/01 l\u00e0<\/p>\n 07012<\/p>\n 81525.<\/p>\n Theo c\u00e1ch t\u00ednh tr\u00ean s\u1ebd c\u00f3 c\u1eb7p s\u1ed1 \u0111\u01b0\u1ee3c d\u1ef1 \u0111o\u00e1n l\u00e0: 25-52<\/p>\n Vi\u1ec7c soi c\u1ea7u d\u1ef1 \u0111o\u00e1n kh\u00f4ng d\u1ec5 d\u00e0ng, b\u1ea1n c\u1ea7n h\u1ecdc h\u1ecfi h\u00e0ng ng\u00e0y \u0111\u1ec3 t\u0103ng th\u00eam nh\u1eefng ki\u1ebfn th\u1ee9c, k\u0129 n\u0103ng. V\u1edbi c\u00e1c chuy\u00ean gia soi c\u1ea7u<\/strong> c\u0169ng c\u1ea7n kh\u00f4ng ng\u1eebng h\u1ecdc t\u1eadp v\u00e0 n\u00e2ng cao. B\u1edfi quy lu\u1eadt c\u1ea7u xu\u1ea5t hi\u1ec7n c\u00f3 th\u1ec3 thay \u0111\u1ed5i t\u1eebng ng\u00e0y. Ch\u00fac c\u00e1c b\u1ea1n s\u1edbm th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c nhi\u1ec1u d\u1ef1 \u0111o\u00e1n pha c\u1ea7u \u0111\u1eb9p.<\/p>\n <\/p>\nC\u01a1 b\u1ea3n \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc l\u00f4 xi\u00ean<\/h2>\n
Soi c\u1ea7u d\u1ef1 \u0111o\u00e1n l\u00f4 xi\u00ean qua k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1<\/h2>\n
k\u1ebft qu\u1ea3 soi c\u1ea7u cao c\u1ea5p
<\/h3>\n